Optimal. Leaf size=155 \[ \frac{15 \sqrt{\pi } b^{5/2} e^{a/b} \text{Erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{16 c}-\frac{15 \sqrt{\pi } b^{5/2} e^{-\frac{a}{b}} \text{Erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{16 c}+\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.406392, antiderivative size = 155, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.583, Rules used = {5653, 5717, 5779, 3308, 2180, 2204, 2205} \[ \frac{15 \sqrt{\pi } b^{5/2} e^{a/b} \text{Erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{16 c}-\frac{15 \sqrt{\pi } b^{5/2} e^{-\frac{a}{b}} \text{Erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{16 c}+\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 5653
Rule 5717
Rule 5779
Rule 3308
Rule 2180
Rule 2204
Rule 2205
Rubi steps
\begin{align*} \int \left (a+b \sinh ^{-1}(c x)\right )^{5/2} \, dx &=x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{1}{2} (5 b c) \int \frac{x \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{\sqrt{1+c^2 x^2}} \, dx\\ &=-\frac{5 b \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}+\frac{1}{4} \left (15 b^2\right ) \int \sqrt{a+b \sinh ^{-1}(c x)} \, dx\\ &=\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{1}{8} \left (15 b^3 c\right ) \int \frac{x}{\sqrt{1+c^2 x^2} \sqrt{a+b \sinh ^{-1}(c x)}} \, dx\\ &=\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{\sinh (x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{8 c}\\ &=\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}+\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{e^{-x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{16 c}-\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{e^x}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{16 c}\\ &=\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}+\frac{\left (15 b^2\right ) \operatorname{Subst}\left (\int e^{\frac{a}{b}-\frac{x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c x)}\right )}{8 c}-\frac{\left (15 b^2\right ) \operatorname{Subst}\left (\int e^{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c x)}\right )}{8 c}\\ &=\frac{15}{4} b^2 x \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{2 c}+x \left (a+b \sinh ^{-1}(c x)\right )^{5/2}+\frac{15 b^{5/2} e^{a/b} \sqrt{\pi } \text{erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{16 c}-\frac{15 b^{5/2} e^{-\frac{a}{b}} \sqrt{\pi } \text{erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{16 c}\\ \end{align*}
Mathematica [A] time = 3.10819, size = 282, normalized size = 1.82 \[ \frac{\sqrt{b} e^{-\frac{a}{b}} \left (\frac{4 \sqrt{b} \left (-2 a^2 e^{\frac{2 a}{b}} \sqrt{\frac{a}{b}+\sinh ^{-1}(c x)} \text{Gamma}\left (\frac{3}{2},\frac{a}{b}+\sinh ^{-1}(c x)\right )-2 a^2 \sqrt{-\frac{a+b \sinh ^{-1}(c x)}{b}} \text{Gamma}\left (\frac{3}{2},-\frac{a+b \sinh ^{-1}(c x)}{b}\right )+e^{a/b} \left (a+b \sinh ^{-1}(c x)\right ) \left (5 \left (3 b c x-2 a \sqrt{c^2 x^2+1}\right )+2 \sinh ^{-1}(c x) \left (4 a c x-5 b \sqrt{c^2 x^2+1}\right )+4 b c x \sinh ^{-1}(c x)^2\right )\right )}{\sqrt{a+b \sinh ^{-1}(c x)}}+\sqrt{\pi } \left (-\left (4 a^2-15 b^2\right )\right ) e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )+\sqrt{\pi } \left (4 a^2-15 b^2\right ) \text{Erfi}\left (\frac{\sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )\right )}{16 c} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.048, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b{\it Arcsinh} \left ( cx \right ) \right ) ^{{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{\frac{5}{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]